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4m^2+25m+34=0
a = 4; b = 25; c = +34;
Δ = b2-4ac
Δ = 252-4·4·34
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-9}{2*4}=\frac{-34}{8} =-4+1/4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+9}{2*4}=\frac{-16}{8} =-2 $
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